We will find out Addition and Subtraction of Units of Measurement.
Addition and subtraction of metric steps can be done as we include and.
deduct regular numbers taking into consideration the location worth of each.
metric measurement.
We can include the systems of measurement like decimal numbers.
I. Addition of Units of Measurement:
Addition of measurements is similar to any other addition.
Observe the copying:
( i) Addition of Length:
1. Add 5 m 9 dm and 11 m and 5 dm
Solution:
5 m 9 dm = 5.9 m
11 m 5 dm = 11.5 m
Hence, 5 m 9 dm + 11 m 5 dm
= 17 m 4 dm or 17.4 m
2. Add 15 cm 5 mm and 21 cm 9 mm
Solution:
15 cm 5 mm = 15.5 cm
21 cm 9 mm = 21.9 cm
Hence, 15 cm 5 mm + 21 cm 9 mm
= 37 cm 4 mm or 37.4 cm
3. Add 67 km 250 m and 84 km 720 m
Solution:
67 km 250 m = 67.250 km
84 km 720 m = 84.720 km
Hence, 67 km 250 m + 84 km 720 m
= 151 km 970 m or 151.97 km
We can include lengths like regular numbers.
4. Add 24 km 250 m and 140 km 18 m
Solution:
24 km 250 m = 24.250 km
140 km 18 m = 140.018 km
Hence, 24 km 250 m + 140 km 18 m
= 164 km 268 m or 164.268 km
More issues on Addition of Units of Length
5. Add 65 km 146 m and 29 km 950 m.
Solution:
Write in column kind and include
Add the meters
146 + 950 = 1096 m
1096 m = 1 km + 96 m
Write 96 under the meter column and rollover 1 km to km column.
Add kilometres 65 + 29 + 1 (rollover) = 95 km
65 km 146 m + 29 km 950 m = 95 km 96 m.
Addition of Metric Measurements:
6.
Add 17 km 540 m; 12 km 800 m; 154 km 325 m Solution:
Step I:
Add metres
540 + 800 + 325 = 1665 m= 1 km + 665 m
Step II: Write 665 under metres and bring 1 to km
Step III: Add kilometres
1 + 17 + 12 + 15 = 45 km
Step IV:
Write 45 under kilometres.
The amount is 45 km 665 m.
7.
Add 13 metre 42 centimetre and 5 metre 26 centimetre.
Step I: Add centimetres
42 + 26 = 68 cm Step II:
Write 68 under centimetres
Step III: Add metres
13 + 5 = 18 m
Step IV:
Write 18 under metres.
The amount is 18 metre 68 centimetre or, 18 m 68 cm.
( ii) Addition of Mass: 1.
Add 21 kg 150 gram and 9 kg 325 gram.
Step I: Add grams
150 + 325 = 475 g Step II:
Write 475 under grams
Step III: Add kgs
21 + 9 = 30 kg
Step IV:
Write 30 under kgs. Therefore, the amount is 30 kg 475 gram or, 30 kg 475 g
( iii) Addition of Capacity: 1.
Add 8 litre 420 millilitre and 34 litre 175 millilitre.
Step I: Add millilitres
420 + 175 = 595 mℓ Step II:
Write 595 under millilitres
Step III: Add litres
8 + 34 = 42 ℓ
Step IV:
Write 42 under litres.
Therefore, the amount is 42 litres 595 millilitre or, 42 ℓ 475 mℓ.
II. Subtraction of Units of measurement:
We can deduct the systems of measurement like decimal numbers. Observe the copying:
( i) Subtraction of Length:
1.
Subtract 25 km 340 m from 61 km 180 m
Solution:
Write in column kind and deduct.
As we can not deduct 340 m from 180 m, we obtain 1 km from.
61 km. 61 km ends up being 60 km and 180 m ends up being 1 km = 1000 m + 180 m = 1180 m. Now, deduct 340 km from 1180 m.
1180– 340 = 840
Subtract km 60– 25 = 35 Hence, 61 km 180 m – 25 km 340 m
= 35 km 840 m Subtraction of measurements is simply like any other subtraction.
2.
Subtract 3 metre 12 centimetre from 16 metre 27 centimetre. Step I:
Subtract centimetres
27 – 12 = 15 cm
Step II:
Write 15 under centimetre Step III:
Subtract metres
16 – 3 = 13 m Step IV:
Write 13 under metre. Therefore, the distinction is 13 metre 15 centimetre or, 13 m 15 cm.
( ii) Subtraction of Mass:
Subtraction of Metric Measurements: 1.
Subtract 27 kg 100 g– 15 kg 400 g
Solution: Step I:
400 g can not be deducted from 100 g. Step II:
Borrow 1 kg from 27 kg 1 kg = 1000 g. 1000 g + 100 g = 1100 g
Step III:
Subtract grams 1100– 400 = 700 g
Step IV:
Write 700 under grams.
Step V: Now 27– 1 = 26 stays under kg.
Step VI:
Subtract kgs. 26– 15 = 11 kg
Step VII: Write 11 under kgs. Therefore, the distinction is 11 kg 700 g.
2. Deduct 14 kg 325 gram from 32 kg 758 gram.
Step I: Subtract grams
758 – 325 = 433 gram
Step II: Write 433 under grams.
Step III:
Subtract
kgs
32 – 14 = 18 kgs
Step IV:
Write 18 under kgs.
Therefore, the distinction is 18 kg 433 gram or 18 kg 433 g. 3.
Subtract 28 dg 7 mg from 90 dg
Solution:
28 dg 7 mg = 28.07 dg
90 dg = 90.00 dg
Hence, 90.00 dg – 28.07 dg
= 61 dg 93 mg or 61.93 dg( i) Subtraction of Capacity:
(i) 106 km 811 mMath Only Math( ii) 4 m 91 cm( iii) 12 l 541 ml
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